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2007-01-09 11:30:51 · 5 answers · asked by CelticMoonGoddess 2 in Science & Mathematics Mathematics

5 answers

3x-4y<-12 if ya want it in slope-intercept from here it is
-4y<-12-3x
-4y<-3x-12
y<-3/4x-3 i think. i might have messed in step 3

2007-01-09 11:40:42 · answer #1 · answered by smartbomb314 2 · 0 0

First temporarily remove the inequality and convert to y=mx+b (Slope-Intercept) Form. Therefore y=3/4x+3. Add in the inequality, but be careful on it flipping. Equation would be y>3/4x+4. To graph this, start on the y-intercept 4, and go up 3 units, and over to the right 4. Plot this point. Connect the points (0,4) and (4,7) to create a line, extending this infinitely. Now make the line dotted (either erase or use other method) and shade below the line.

2007-01-09 19:45:18 · answer #2 · answered by the smart kid 2 · 0 0

3x – 4y < -12
-4y < -12 -3x
4y > 12 +3x
y > (3/4)x + 3
Now for a moment think y = (3/4)x + 3
then the y intercept is (0,3) and the x intercept is (-4,0).
Draw a line through these two points but make it dashed because y > (3/4)x +3 , and not equal to it as we temporarily assumed.

Now all the points above the dashed lin satisfy the inequality so you can shade that area.

2007-01-09 19:44:25 · answer #3 · answered by ironduke8159 7 · 0 0

You have to solve for X and Y. Whatever you got for X would be (X,0) on the horizontal axis and whatever you get for Y would be (0,Y) on the vertical axis. plug in a random point on the graph into the equation. if it is true, shade in that direction. if it is false, shade in the opposite direction.

2007-01-09 19:42:58 · answer #4 · answered by elle 2 · 0 0

go to.....http://www.coolmath.com/graphit/index.html

2007-01-09 19:40:28 · answer #5 · answered by Baby J 1 · 0 0

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