3x-4y<-12 if ya want it in slope-intercept from here it is
-4y<-12-3x
-4y<-3x-12
y<-3/4x-3 i think. i might have messed in step 3
2007-01-09 11:40:42
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answer #1
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answered by smartbomb314 2
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First temporarily remove the inequality and convert to y=mx+b (Slope-Intercept) Form. Therefore y=3/4x+3. Add in the inequality, but be careful on it flipping. Equation would be y>3/4x+4. To graph this, start on the y-intercept 4, and go up 3 units, and over to the right 4. Plot this point. Connect the points (0,4) and (4,7) to create a line, extending this infinitely. Now make the line dotted (either erase or use other method) and shade below the line.
2007-01-09 19:45:18
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answer #2
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answered by the smart kid 2
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3x – 4y < -12
-4y < -12 -3x
4y > 12 +3x
y > (3/4)x + 3
Now for a moment think y = (3/4)x + 3
then the y intercept is (0,3) and the x intercept is (-4,0).
Draw a line through these two points but make it dashed because y > (3/4)x +3 , and not equal to it as we temporarily assumed.
Now all the points above the dashed lin satisfy the inequality so you can shade that area.
2007-01-09 19:44:25
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answer #3
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answered by ironduke8159 7
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You have to solve for X and Y. Whatever you got for X would be (X,0) on the horizontal axis and whatever you get for Y would be (0,Y) on the vertical axis. plug in a random point on the graph into the equation. if it is true, shade in that direction. if it is false, shade in the opposite direction.
2007-01-09 19:42:58
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answer #4
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answered by elle 2
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go to.....http://www.coolmath.com/graphit/index.html
2007-01-09 19:40:28
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answer #5
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answered by Baby J 1
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