Calculate the molarity of a hypobromide solution...?

Question

Calculate the molarity of a hypobromide solution if 10.00 mL of the OBr^1- (aq) solution requires 3.52 mg of ammonia for a complete reaction.

2 NH3 (aq) + 3 OBr^1- (aq) --> N2 (g) + 3 Br^1-(aq) +3 H2O.

And why is it called hypobromite?

Thanks!

Answer 1

(0.00352 g NH3)/(17 g/mole NH3)/(2 mole NH3)*(3 mole BrO-)/(0.01 L BrO-) = Answer

With the important step being the mole ratio of 2:3


Halogens with oxygens are named in the following way:

ClO4 --- Perchlorate
ClO3 --- Chlorate
ClO2 --- Chlorite
ClO --- Hypochlorite

You can see the Chlorate/Chlorite naming you are used to like with SO4/SO3 Sulfate/Sulfite. The prefixes show that there are more or less oxygens. Hypo means less like hypothermia.