|2x|=8
|5y-2|=7
|c-3|<1
3-2r|>7
|2g-5|≥9
2007-01-09 11:07:15 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
|2x|=8 ans is 4
|5y-2|=7 ans is -1
|c-3|<1 ans is 4
3-2r|>7 ans is 5 or -5
|2g-5|≥9 ans is 7
lol i guessed on most of em
wait a sec i only missed one and i got a thumbs down???
2007-01-09 11:18:22 · answer #1 · answered by krazy_alzan 4 · 0⤊ 1⤋
I wasn't going to answer, but then I saw the horrible answers you were getting and decided I'd better provide at least one correct one...
|2x| = 8 => 2x = 8 or -8, so x = 4 or -4.
|5y-2| = 7 => 5y - 2 = 7 or -7, so 5y = 9 or -5, so y = 9/5 or -1.
|c-3| < 1 => c-3 < 1 and c-3 > -1, so c < 4 and c > 2, so c ∈ (2, 4).
|3-2r| > 7 => 3-2r > 7 or 3-2r < -7, so -2r > 4 or -2r < -10, so r < -2 or r > 5, so r ∈ (-∞, -2) ∪ (5, ∞)
|2g-5| >= 9 => 2g-5 >= 9 or 2g-5 <= -9, so 2g >= 14 or 2g <= -4, so g >= 7 or g <= -2. So g ∈ (-∞, -2] ∪ [7, ∞).
2007-01-09 11:22:18 · answer #2 · answered by Scarlet Manuka 7 · 0⤊ 1⤋
X=4
5Y=7+2
Y=9/5
OR
Y=-5/5
Y=-1
C<2
R<-2
G>=7
2007-01-09 11:16:03 · answer #3 · answered by well thts it...... 3 · 0⤊ 1⤋
|2x|=8
x=4
|5y-2|=7
y=9/5=1.8
|c-3|<1
c<4
|3-2r|>7
r>5
|2d-5|>/9
d>/7
2007-01-09 11:11:02 · answer #4 · answered by juanita77008 2 · 0⤊ 2⤋
either (1 + 3n/4) = 4 or -(1 + 3n/4) = 4 4 + 3n = 16 or 4 + 3n = -16 n = 4 or n = -4
2016-05-23 01:05:05 · answer #5 · answered by Anonymous · 0⤊ 0⤋
IS this HW?
2007-01-09 11:15:32 · answer #6 · answered by Phish 2 · 0⤊ 1⤋