what is x^2+6x+5=0?

Question

can u show all ur work

Answer 1

x^2+6x+5=0
(x+1)(x+5)

x+1=0
(subtract one from both sides to get: x= -1)

x+5=0
(subtract five from both sides to get x= -5)

Answer 2

You have to factor this equation.
(x + 5) (x + 1) = 0

There are two solutions.
x= -5
x = -1

Substitute into the original formula
x^2 + 6x + 5= 0
-5^2 + (6*-5) + 5 = 0
25 - 30 + 5 = 0
0 = 0 (checks)

Substitute into the original formula
x^2 + 6x + 5= 0
-1^2 + (6*-1) + 5 = 0
1 - 6 + 5 = 0
-5 + 5 = 0
0 = 0 (Checks)

Answer 3

you just have to look and factor it.
(x+5)(x+1) = 0 so
x + 5 = 0 so x = -5
x + 1 = 0 so x = -1

The key in "looking" is deciding what two numbers multiply
together to equal +5. In this problem you could only choose from
(+5) times (+ 1) = 5
or
(-5) times (-1) = 5

pick the pair that will add up to the coefficient on the x (the 6 in 6x)
(+1) + (+5) = 6

Answer 4

Simplifying
x2 + 6x + 5 = 0

Reorder the terms:
5 + 6x + x2 = 0

Solving
5 + 6x + x2 = 0

Solving for variable 'x'.

Factor a trinomial.
(5 + x)(1 + x) = 0

Subproblem 1
Set the factor '(5 + x)' equal to zero and attempt to solve:

Simplifying
5 + x = 0

Solving
5 + x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -5 + x = 0 + -5

Combine like terms: 5 + -5 = 0
0 + x = 0 + -5
x = 0 + -5

Combine like terms: 0 + -5 = -5
x = -5

Simplifying
x = -5
Subproblem 2
Set the factor '(1 + x)' equal to zero and attempt to solve:

Simplifying
1 + x = 0

Solving
1 + x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + x = 0 + -1

Combine like terms: 1 + -1 = 0
0 + x = 0 + -1
x = 0 + -1

Combine like terms: 0 + -1 = -1
x = -1

Simplifying
x = -1
Solution
x = {-5, -1}

Answer 5

x= -1 and -5

(x+1)(x+5)

(x+1)(x+5) = x^2 + 5x + 1x + 5 = x^2 +6x + 5

You then have to make both numbers in the paranthesis equal zero, so: (x+1)(x+5) would be (-1 +1)(-5 +5) to be (0)(0). So the answer is x equals -1 and -5

Answer 6

x is equal to -1 or -5


you have to factor the equation into
(x+1)(x+5)=0

then just find what number makes each of the parenthese equal zero
-1+1=0, or -5+5=0

Answer 7

u have to factor x-squared+6x+5 into
(x+1)(x+5)

so u get (x+1)(x+5)=0 and inorder for this to b tru x has to be negative 1 and negative 5

x= -1, -5

Answer 8

you need to factor
(x + 5)(x + 1)
Check: (* is multiplication)
[x * x = x^2]
[x*1 + 5 *x = 6x]
[5*1= 5]
set them each to the zero and solve
x +5 = 0
x = -5

x +1 = 0
x = -1

you have two answer x= -5 and x = -1

Answer 9

x=-2 and x=-3 i dont feel like showing the work

Answer 10

it's a quadratic equation with the y-intercept (0, #) as 0,5