Specific heat homework HELP?

Question

Iron which is 449 c(J/kg K) into Calories
which is at
specific heats at 25 degrees celcius
Need help

If Iron is 449 c(J/kg K)

how do you find how much calories that is?

Answer 1

The key here is to understand that all you are converting is the Joules to Calories.

4.184 Joule = 1 Calorie

So:
449 (J/kg K) * 1 calorie / 4.184 Joule = 107.3 (cal/kg K)

Answer 2

Keith - this is been a real long term for me on account that chemistry... and that i'm, needless to say, "winging" this: to advance the temperature of the 250 g of water with the aid of 1ºC demands 250 x 4.184 = a million,046 J. To get that lots warmth out of 155g of Cu the copper will would desire to take a seat back (a million,046)/(.385 x a hundred and fifty five) = 17.53ºC the in simple terms authentic temperature... of path... would be T. The copper cools 17.fifty 3 situations as lots simply by fact the water warms the version between the nice and comfortable copper and the cool water is, initially, a hundred thirty.2 C tiers. i'm questioning of the temperature hollow remaining in increments of 18.fifty 3 C tiers. that's by technique of the fact, for each 1º improve in water temp., there's a 17.53º shrink interior the copper's temp... 18.53º closure. a hundred thirty.2/18.fifty 3 = 7.02. there will be 7 of those 1º water temp. will improve; water temp. ends at 26.8º. permit's verify: If the copper cooled an entire of seven x 17.53º it is going to cool approximately 123.2º. that would have the copper end at a hundred and fifty - 123.2 = 26.8º sure! do not you in simple terms like it while it relatively works? Richard