The formula is H= -Plog(P) The log is to base 2, not 10.
I have an answer but do not know how it is calculated.
P=0.39 which gives H=0.53
can someone tell me how this is?
2007-01-09 10:40:45 · 3 answers · asked by crip_pler2003 2 in Science & Mathematics ➔ Mathematics
I'm not sure what you don't understand with this. Just plug the number in.
To avoid tables I will use approximations. 0.39 is about 0.375 = 3/8, so let's use that instead.
-3/8*log2(3/8) = -3/8*(log2(3) - log2(8))
= -3/8*(1.6 - 3) (I am using 1.6 for log2(3). sqrt(2) = 1.41, so 2^(1.5) is about 2.82)
= -3/8*(-1.4) = 4.2/8 = .525, not bad for approximations.
2007-01-09 11:00:30 · answer #1 · answered by sofarsogood 5 · 0⤊ 0⤋
The relation between the various log functions is: if X = log10(y), then X = 0.30103 log2(y). The number 0.30103 is the logarithm of 2 to base 10.
2007-01-09 18:57:37 · answer #2 · answered by Anonymous · 0⤊ 0⤋
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2007-01-09 19:05:37 · answer #3 · answered by modulo_function 7 · 0⤊ 0⤋