there are seven more quaters than there are dimes.How many dimes and quaters are there if the collection is worth $3.50?
2007-01-09 10:35:48 · 4 answers · asked by datfreshness 1 in Education & Reference ➔ Homework Help
first choose two variables to stand for the coins..
q = number of quarters
d = number of dimes
then make two equations...
d = q+7 (there are seven more quarters than dimes)
0.1d+0.25q = 3.5 (the value of the coins times the number of coines equals $3.50)
then plug in the first equation into the second and solve for the other variable...
0.1(q+7) + 0.25q = 3.5 which simplifies into...
0.1q + 0.25q + .7 = 3.5 subtract .7 and combine the q's
.35q = 2.8 then divide by .35
q = 8 then plug this solution into the origional first
d = 8+7 = 15
so you have 8 quarters ($2) and 15 dimes ($1.5)
(2 + 1.5 = 3.5)
2007-01-09 10:50:52 · answer #1 · answered by luisfernu@sbcglobal.net 2 · 0⤊ 0⤋
12 quarters 5 dimes
2007-01-09 18:42:44 · answer #2 · answered by anonomys 2 · 0⤊ 0⤋
12 quarters = $3.00
5 dimes= $0.50
2007-01-09 18:51:12 · answer #3 · answered by G 2 · 0⤊ 0⤋
Not enough to buy much
2007-01-09 19:00:28 · answer #4 · answered by Anonymous · 0⤊ 0⤋