(n+3)(2n+3)=(n+2)^2+(n-2)^2?

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(n+3)(2n+3)=(n+2)^2+(n-2)^2?

Need help can't solve and no my math book doesn't say anything about the problem. Need to solve for n. )^2 means that (n+2) is to the 2nd power. and thats mainly the part i don't get. PLEASE HELP!!!

2007-01-09 09:57:19 · 2 answers · asked by Me 2 in Education & Reference ➔ Homework Help

2 answers

2n^2 +9n+9=2n^2+8
9n+9=8
9n=1
n=1/9

2007-01-09 10:05:47 · answer #1 · answered by adriantheace 4 · 0⤊ 0⤋

(n+3)(2n+3)=(n+2)(n+2)+(n-2)(n-2)
2n^2+9n+9= 2n^2+8
subtract 2n^2
9n+9=8
subtract 9
9n= -1
n= -1/9

buddy above you gotta subtract 9 not 7

2007-01-09 18:09:03 · answer #2 · answered by Zaza 5 · 1⤊ 0⤋