222 michael lane stroudsburg pa 18360
2007-01-09 09:20:47 · 4 answers · asked by mapleleaf9013 1 in Science & Mathematics ➔ Geography
Approximately:
41° 1' 25" N
75° 23' 8" W
2007-01-09 10:32:28 · answer #1 · answered by Keith P 7 · 0⤊ 0⤋
Divide 18360 by 222. That gives you 82.7
Divide 222/82.7, square the result, and subtract it from your first result. That gives you a longitude of about 75.3 W.
Drop the zero off the zip code, use FLEA to resequence your number. I.e. - first digit is 1, last digit is 6, inside digits, in order are 8 and 3. Take the square root of the resequenced number. That gives you a latitude of about 41 degrees.
2007-01-09 10:02:41 · answer #2 · answered by Bob G 6 · 0⤊ 0⤋
Google Earth
2007-01-09 09:35:33 · answer #3 · answered by paradise 4 · 0⤊ 0⤋
http://terraserver.microsoft.com/image.aspx?T=1&S=10&Z=18&X=2383&Y=22676&W=1&qs=Storm+Road|Stroudsburg|PA&Addr=Storm+Rd%2C+Stroudsburg%2C+PA+18360&ALon=-75.2783562&ALat=40.9661872
2007-01-09 09:59:52 · answer #4 · answered by whatever 4 · 0⤊ 0⤋