The area of a rectangle is 45 square inches. One dimension is 5 inches.What is the perimeter?
2007-01-09 09:07:08 · 22 answers · asked by Makayla 1 in Science & Mathematics ➔ Mathematics
28 in. is the answer
To find the area of a rectangle you multiply the width by the length.
If the area is 45 and one dimension is 5 then you know that 9 *5 gives you 45 so the other dimension is 9.
Then to find perimeter you add all sides of the rectangle.
So it would be 9 + 9 + 5 + 5 = 28
2007-01-09 09:12:39 · answer #1 · answered by Sin4lyContagious 2 · 0⤊ 0⤋
If the rectangle is 45 inches then the other dimension is 9 inches (9 x 5 = 45)
The perimeter would be 9+ 5 + 9 + 5 = 28 inches
2007-01-09 09:12:41 · answer #2 · answered by David B 2 · 0⤊ 0⤋
If the area is 45, and one side is 5, then the other side must be 9. So the perimeter is 9+5+9+5 = 28.
2007-01-09 09:20:34 · answer #3 · answered by Anonymous · 0⤊ 0⤋
45 /5 =9 5+5+9+9=28
2007-01-09 09:13:28 · answer #4 · answered by spiritbx 3 · 0⤊ 0⤋
if the area is 45 and one dimension is 5 .... 9 x 5 = 45 so two sides r 9 and 2 sides r 5 so 10 + 18 = 28
2007-01-09 09:11:29 · answer #5 · answered by Brittany B 2 · 0⤊ 0⤋
28 because 9+9+5+5 is 28
2007-01-09 09:18:41 · answer #6 · answered by michelleee♥ 5 · 0⤊ 0⤋
S=AxB (A&B dimensions,s-area)
45=5xB
B=45/5=9
P(perimeter)=5+5+9+9=28
2007-01-09 09:16:45 · answer #7 · answered by torta 1 · 0⤊ 0⤋
28 in. because it would be 5x=45 where x=9. SO because i is a rectangle 2 sides are 9 in. and 2 sides are 5 in. so 9+9+5+5=28 in
2007-01-09 09:15:32 · answer #8 · answered by Anonymous · 0⤊ 0⤋
area = side x side
area = 5 x side
area = 5 x 9 (45)
perimeter = 9 & 9 & 5 & 5 =28.
Does that help cutie?
2007-01-09 09:12:26 · answer #9 · answered by Anonymous · 0⤊ 0⤋
A=h*w
45=5*w
therefore w=9
Perimeter=2w+2h
so, Per=10+18=28
2007-01-09 09:11:37 · answer #10 · answered by ENA 2 · 1⤊ 0⤋