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C (s) + SO2 (g) ---> CS2(g) + CO(g)

How many liters of SO2 are required to make 152 grams of CS2?

2007-01-09 08:43:10 · 2 answers · asked by Anonymous in Science & Mathematics Chemistry

2 answers

1) First the balanced equation:

5C (s) + 2SO2 (g) ---> CS2(g) + 4CO(g)

2) We need 2 moles of SO2 to produce 1 mol of CS2.
How many moles there are in 152 grams of CS2?
n = 152 g / 76 g/mol = 2 moles (76 g/mol is the molecular mass of CS2)

3) 2 moles of SO2 = 1 mol of CS2......hence:
......................x......= 2 mol of CS2

x = 4 moles of SO2

4) Assuming you are working in Standard Conditions 1 mol of a gas is equal to 22.4 liters, so:

1 mol ........= 22.4 L
4 moles= x

x = 89.6 L of SO2

That's it!

Good luck!

2007-01-09 09:06:07 · answer #1 · answered by CHESSLARUS 7 · 0 0

First of all, you need to balance your equation. As of now on the left you have: 1C, 1S, 2O. On the right, you have: 2C, 2S, 1O. I am not going to balance it for you.

Next, remember that 1 mole of substance = 22.4L (liters). You can figure out grams from moles by calculating the molar mass of CS2 from your periodic table. Molar mass is in units of grams/mole, and you now know that there is 1 mol/22.4L. Make a proportion with your known amount of CS2 (152g) and its molecular weight and you will have moles of CS2. You can then convert to liters!

Hope this helped.

2007-01-09 08:55:21 · answer #2 · answered by Anonymous · 0 0

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