2007-01-09 07:23:23 · 6 answers · asked by Anonymous in Education & Reference ➔ Homework Help
first guy is half right !!
square root of 121 is either +11 or -11
so (x+6) has to equal 11 or -11....
so x is either +5 or -17
2007-01-09 07:35:01 · answer #1 · answered by Tiberius 4 · 1⤊ 0⤋
No, Tiberius is correct.
You use the square root for both sides of the equation (what you do to one side you must do to the other)
the square root of (x+6)^2 is just (x+6)
the square root of 121 is +11 or -11 (because either squared would equal +121)
then solve for both equations, and both answers are used
x+6 = 11 and x+6=-11
2007-01-09 07:55:35 · answer #2 · answered by Leah M 3 · 0⤊ 0⤋
11 squared is 121. So x=5, since 5 +6 =11
2007-01-09 07:26:18 · answer #3 · answered by theeconomicsguy 5 · 0⤊ 0⤋
(x + 6)² = 121 Taking the sq. root on the two aspects, x + 6 = 11; subsequently x = 5. that's the obtrusive answer; yet, in extracting the sq. root of 121, -11 is likewise a valid consequence. hence, x = -17.
2016-12-12 07:49:37 · answer #4 · answered by motato 4 · 0⤊ 0⤋
Tiberius is definitely right. The quadratic equation has nothing to do with it at all. Period.
2007-01-09 08:49:57 · answer #5 · answered by sprake2466 2 · 0⤊ 0⤋
the previous answer is not right at all!!! you don't know how to solve quadratic equation!!!
x1=85 and x2=73
2007-01-09 07:38:30 · answer #6 · answered by Yorik 2 · 0⤊ 0⤋