Consider the ideal gas law: PV=NkT, where:
P= pressure
V= volume
N= number of molecules
k= Boltzman's constant
T= temperature.
A reduction in temperature must either reduce the pressure, or the volume of the gas, since the number of molecules of air won't change. Now, the balloon surface is held in place because the pressure inside and outside the balloon is balanced. The air pressure in the freezer is the same as that outside of it, since it's not actually airtight (somewhere in the back there must be a vent, because otherwise you wouldn't be able to pull the door open). With the pressure and number of molecules unchanged, we are left with the fact that the lower temperature leads to a smaller volume.
If you want a physically intuitive way of looking at it, the lower temperature means the molecules of air move slower, and they can't force the rubber balloon surface outwards as much.
2007-01-09 07:36:42
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answer #1
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answered by Anonymous
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The actual "reason" that this happens is that the air molecules inside the warmer balloon are in a more excited state, colliding with each other more forcefully and pushing each other farther apart. The more forcefully they interact with each other, the more space they will take up. When the air cools, the molecules slow down and interact less forcefully, causing them to settle and the elastic balloon which is putting inward force on the air causes it to contract.
2007-01-09 07:45:26
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answer #2
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answered by Anonymous
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Balloons are stuffed with gasoline (enable's say air). whilst gases are cooled, the rigidity is going down, however the forces exerted by potential of the balloon dermis proceed to be in reality consistent (ok, they shrink somewhat, yet no longer as lots as a results of fact the rigidity of the gasoline). the floor of the balloon compresses the cooled air at decrease temperature, for this reason a smaller balloon.
2016-12-16 05:29:33
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answer #3
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answered by wilma 3
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the volume a certan nomber of molicules take up is proportional to the temperator it is at so
for example room temperator 23 degres C or 296k 1 moe of gass (the mole ben 6.022 x10^23 molicules) ocupis 24dm^3
wher as at 0 degres C or 273k 1 moe of gassocupis 22.22 dm^3 aproximatly
2007-01-09 07:28:38
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answer #4
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answered by Michael D 6
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Because as temperature drops, the same amount of gas takes less space.
It is expressed with the formula PV = nRT
where n(amount of gas), P(pressure 1 atm), R(gas constant) are constants for the baloon, as T(temperature) goes down, V also does to maintain the equality.
2007-01-09 07:24:05
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answer #5
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answered by panpis 2
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As the airin the balloon cools, the rubber of the balloon can compress it further. If you warmed the air up, the balloon would get bigger.
2007-01-09 07:19:53
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answer #6
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answered by Anonymous
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Pressure * Volume is proportional to Mass * Temperature
This is the perfect gas law. If Temperautre goes up, pressure and volume tend to rise. If T goes down, P and V tend to lower.
2007-01-09 07:18:46
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answer #7
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answered by Holden 5
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The volume of a fixed quantity of cold air is less than the volume of the same quantity of warm air
2007-01-09 11:14:06
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answer #8
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answered by rosie recipe 7
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Because the air inside it contracts when it cools, reducing the outward pressure on the baloon. (It's just how gasses behave)
2007-01-09 07:19:33
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answer #9
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answered by nealo d 5
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Because cold air takes up less space.
2007-01-09 07:17:25
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answer #10
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answered by Anonymous
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