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5 answers

0.15uF

2007-01-09 06:03:43 · answer #1 · answered by chopchubes 4 · 0 0

You would half the value of the caps. So it would be .3/2 or .15 uf. On caps. it works kinda opposite of resistors, in series resistors are additive not caps.

2007-01-09 06:06:41 · answer #2 · answered by mr.answerman 6 · 0 0

Since Capacitance is the product of the capacitors divided by the sum of the capacitors ...

(0.3*0.3)/(0.3+0.3) = 0.9/0.6 = 1.5uf

2007-01-09 06:53:11 · answer #3 · answered by icehoundxx 6 · 0 0

CT = C1 × C2/(C1+C2)

=(20.3uf*20.3uf)/(20.3uf+20.3uf)
=(412.09uf*1uf)/(40.6uf)
=412.09uf/40.6
=10.15uf
total capacitance is 10.15uf

2007-01-09 06:06:46 · answer #4 · answered by dorjay2002 1 · 0 0

Sh*t...Thats a hard one,, Can you give us a clue????

2007-01-09 10:54:59 · answer #5 · answered by pop c 2 · 0 0

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