These are fractions the 2 is the numerator and the 5w+10 is the denominator and 3 is the numerator and the 2w-4 in the denominator. Also this question is subtraction. Thanks
2007-01-09 05:23:29 · 8 answers · asked by Jill K 1 in Science & Mathematics ➔ Mathematics
First: factor the denominators...
[2/5w + 10] - [3/2w - 4]
[2/5(w + 2)] - [3/2(w - 2)]
*Determine the (LCD) Least Common Denominator > combine all the denominators > (5)(w + 2)(2)(w - 2) ...
Sec: multiply each denominator by the missing terms to get the LCD > and then multiply the same missing terms by the numerator...
[(2)(w-2)(2)]/[(2)(w-2)(5)(w+2)] - [(5)(w+2)(3)]/[(5)(w+2)(2)(w-2)]
*Combine the numerators...
[2(2)(w-2)]/[(2)(5)(w-2)(w+2)] - [5(3)(w+2)]/[5(2)(w+2)(w-2)]
[4(w - 2)]/[10(w - 2)(w + 2)] - [15(w + 2)]/[10(w - 2)(w + 2)]
[4w - 8]/[10(w - 2)(w + 2)] - [15w + 30]/10(w - 2)(w + 2)]
Third: combine the numerators...
[4w - 8 - 15w - 30]/10(w - 2)(w + 2)
[-11w - 38]/10(w - 2)(w + 2)
2007-01-09 05:52:29 · answer #1 · answered by ♪♥Annie♥♪ 6 · 0⤊ 0⤋
first team each of the w's and numbers jointly. so it would want to be: 2/5w-3/2w+10-4 now you may come across a effortless denominator for 2/5 and three/2. the most obtrusive you are able to nonetheless be 10. so u change the fractions to 4/10w-15/10w+10-4. then you definitely remedy from left to accurate: 4/10w-15/10w+10-4 -11/10+6 or -a million a million/10w +6
2016-12-28 13:00:29 · answer #2 · answered by ? 4 · 0⤊ 0⤋
= 2(2w - 4) - 3(5w+10) / (5w +10)(2w - 4)
= 4w - 8 - 15w -30 / (5w +10)(2w - 4)
= -11w - 38 / (5w +10)(2w - 4) = answer.
that answer should be acceptable. i don't think you need to expand the eq of the LCD.
2007-01-09 05:35:50 · answer #3 · answered by jedoneseventhree 3 · 1⤊ 1⤋
2/(5w+10)-3/(2w+4)=0 <=> 2(2w+4) -3(5w+10)=0 => 4w+8-15w-30=0 => -11w-22=0 => -11w=22 => -w=22/11 <=> -w=2 <=> w=-2 this is the solution :)
2007-01-09 05:51:00 · answer #4 · answered by HeAvEnLy_PiNk 3 · 0⤊ 4⤋
2/5w+10 - 3/2w-4
2(2w-4) - 3(5w+10)/5w+10(2w-4)
4w-8-15w-30/10w^2-20w+20w-40
-11ww-38/-40+10w
=11w+38/40-w^2
2007-01-09 05:29:27 · answer #5 · answered by miinii 3 · 0⤊ 1⤋
This is the answer
-1/2w + 6
2007-01-09 05:27:17 · answer #6 · answered by d1314151617181920 2 · 0⤊ 4⤋
okay, so you have
2/5(w+2) - 3/2(w-2)
The least common denominator is 2 * 5 * (w+2) (w-2)
Multiplying both fractions to get to the LCD for both:
2*2*(w-2)/LCD - 3*5*(w+2) / LCD
(4w-8 - 15w-30)/LCD
(-11w-38)/LCD
2007-01-09 05:29:50 · answer #7 · answered by bequalming 5 · 1⤊ 2⤋
?
2007-01-09 05:26:39 · answer #8 · answered by lizzalicious 2 · 0⤊ 3⤋