how many hops do u have to do,before his back Breaks?
2007-01-09 05:21:56 · 10 answers · asked by Anonymous in Sports ➔ Wrestling
No. I wanted to be put in it to see how much it hurts and how much I can take, but I've never had anybody able to do it.
2007-01-09 07:05:28 · answer #1 · answered by Ash 5 · 0⤊ 0⤋
A normal hop from a normal person won't do it. You'd need to maybe hop off your porch, or off of the ring apron. At least a 3ft drop. The down force is necessary. Apply a tighter hold and a higher drop for larger people.
p.s. Breaking someones back is considered assault, and assault & battery if you're trained. This may also cause paralisys, or death, so don't try it at home!
2007-01-09 06:45:55 · answer #2 · answered by Harry A 6 · 0⤊ 0⤋
Lex Luger is one of the few guys to be able to rack Paul 'The Giant' Wight, which is as impressive as John Cena FU'ing the same guy. Lex is totally underrated in my opinion, although he is a certified jackass
2016-05-22 23:10:34 · answer #3 · answered by Anonymous · 0⤊ 0⤋
Yes i have ...and i have been in it...not sure how many hops it would take...but its more about the pressure your arms are appling bringing the upper and lower body down during the hops....Its a fun move to do to someone ..its not so fun when your in it.
2007-01-09 05:32:00 · answer #4 · answered by Pierced00 3 · 0⤊ 0⤋
Let's find out
a one
a twohoo
a three
(crunch)
A three.
The world may never know.
2007-01-09 15:31:00 · answer #5 · answered by Anonymous · 0⤊ 0⤋
I used to do it to my little brother all the time, he said it hurts like hell.
2007-01-09 05:26:29 · answer #6 · answered by j.soto416 2 · 0⤊ 0⤋
yeah I used to do this to people when I was in Middle School..
2007-01-09 05:29:23 · answer #7 · answered by Byakuya 7 · 0⤊ 0⤋
his back wont break believe me ive been in one
2007-01-09 05:26:21 · answer #8 · answered by brian g 2 · 0⤊ 0⤋
http://en.wikipedia.org/wiki/Backbreaker#Argentine_backbreaker_rack
2007-01-09 05:39:40 · answer #9 · answered by grant212021 4 · 0⤊ 0⤋
That is fake
2007-01-09 05:33:39 · answer #10 · answered by Anonymous · 0⤊ 0⤋