It takes 7 shipping clerks 15 days to prepare the warehouse for a new shipment. How many days would it take if only 3 shipping clerks, who worked at the same rate, had to do the job?
could anyone help me solve this problem i roughly know the answer is more then 30 days but whats the formula thanks
2007-01-09 03:58:23 · 11 answers · asked by elearner 1 in Science & Mathematics ➔ Mathematics
Work out the number of "man-days" for the task = 7*15 = 105 man days
Now assuming there are no critical tasks that require one clerk to wait on another and the job can be split up linearly.
Given 3 clerks, combined they have to provide 105 man days for a new shipment, which is 35 days each - so as they work in parallel the new shipment takes 35 days.
Now if we could work out how many shipping clerks it takes to change a light bulb...
2007-01-09 04:05:29 · answer #1 · answered by Andy 2 · 0⤊ 0⤋
First you find out how much time would a single shipping clerk take. That means you have to multiply 15 by 7 because you multiplied the 7 clerks by 7. You get 105 days. Now to get the rate of the 3 clerks you divide the 105 by 3 (to go from single clerk to 3) and you get 35. That means that 3 clerks take 35 days to prepare a warehouse.
2007-01-09 12:11:22 · answer #2 · answered by galblatman 2 · 0⤊ 0⤋
If C = number of clerks and N = days then C*N = number of clerk days required to complete the job.
In your problem we have C = 7 and N = 15 therefore there are 7*15 or 105 clerk days required to complete the job.
If we had only 3 clerks our formula would be 3 * N = 105. Therefore N would be 105/3 = 35. It would take 35 days to complete the job with 3 clerks.
2007-01-09 12:19:39 · answer #3 · answered by 1ofSelby's 6 · 0⤊ 0⤋
The work required to prepare the warehouse = 7 * 15 clerk/days = 105.
Therefore if you have only 3 shipping clerks it will take them 105/3 = 35 days.
2007-01-09 12:03:36 · answer #4 · answered by Matthew H 3 · 1⤊ 0⤋
7 clerks = 15 days
1 clerk = 7 x 15 = 105 days
3 clerks = 105 divided by 3 = 35 days
2007-01-09 13:09:11 · answer #5 · answered by David C 2 · 0⤊ 0⤋
7 workers 15 days
3 workers more days
you got 7 * 15 = 105 (worker x day ratio)
So it'll take 105 / 3 = 35 days to complete with 3 workers
2007-01-09 12:03:36 · answer #6 · answered by The Soulforged 2 · 1⤊ 0⤋
7 clerks take......15 days
1 clerk will take ...105 days
3 clerks will take...105/3=35 days
2007-01-09 12:04:57 · answer #7 · answered by openpsychy 6 · 1⤊ 0⤋
7/3 * 15
7/3=2.33 so 7 is 2.33 times more than 3. Therefore you need 2.33 times more days to do the work so 2.33 X 15= 35 days
2007-01-09 12:03:57 · answer #8 · answered by Hidden 2 · 1⤊ 0⤋
If they are non-union & making minimum wage it will only take them 9 days.
2007-01-09 12:01:50 · answer #9 · answered by workingclasshero 5 · 0⤊ 1⤋
They're union, working class. That's how we know that the work rate is rigid. :o)
2007-01-09 12:07:57 · answer #10 · answered by bequalming 5 · 0⤊ 1⤋