Find exactly: sin 30˚ cos 45˚
2007-01-09 03:52:12 · 9 answers · asked by thomasgraham880 1 in Science & Mathematics ➔ Mathematics
sin 30* = 0.5
cos 45* = 1/squareroot2 (or 0.707)
2007-01-09 03:57:24 · answer #1 · answered by Beverley B 2 · 0⤊ 0⤋
sin 30=1/2
cos 45= Square root of 2/2
2007-01-09 11:57:52 · answer #2 · answered by JCrazy84 3 · 0⤊ 0⤋
sin30 = 1/2
and cos 45 = 1/root 2
therefore sin30cos45 = 1/ (2 times root2)
2007-01-12 02:40:19 · answer #3 · answered by inamoto ichiban 2 · 0⤊ 0⤋
sin 30=1/2
cos45=2^1/2
sin30 cos45= 1/2*2^1/2
=^1/2
= .70710678118654....
2007-01-09 12:10:45 · answer #4 · answered by yason 2 · 0⤊ 0⤋
sin(30)=1/2
cos(45)=sqrt2/2
2007-01-09 12:13:29 · answer #5 · answered by Rich 1 · 0⤊ 0⤋
Those are true in degrees.
Rad:-0.519034
Grad:0.345217
These are derived from a calculator,you can calculate their exact values using a scientific calculator.
2007-01-09 12:01:51 · answer #6 · answered by Cheng J 2 · 0⤊ 0⤋
=1/(2sqrt2)
2007-01-09 12:00:20 · answer #7 · answered by Maths Rocks 4 · 0⤊ 0⤋
1/2,1/sqrt2
2007-01-09 12:01:16 · answer #8 · answered by openpsychy 6 · 0⤊ 0⤋
0.25*(2)^1/2
2007-01-09 11:59:23 · answer #9 · answered by Anonymous · 0⤊ 0⤋