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How much of a beam of randomly polarized light will pass through a pair of polarizers set at a45 degree angle between the two?

2007-01-09 02:21:53 · 2 answers · asked by kid_A 2 in Science & Mathematics Physics

2 answers

50% and this is why:

according to Malus Law
I=I(initial)(cos(A))^2

cos(45)=sqrt(2)/2
(cos(45))^2=(sqrt(2)/2)^2=1/2 or 50%

2007-01-10 03:14:03 · answer #1 · answered by Edward 7 · 0 0

Through the first polarizer: Half the intensity (Check your physics textbook)
Through the second polarizer: (half the intensity)xcos^2(45 degrees). Isn't the Malus law I=cos^2φ(Io) or do not I remember right?

2007-01-10 03:24:02 · answer #2 · answered by supersonic332003 7 · 0 0

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