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i don't get how to do them here are a few of them

Factor:
15a^3-6a^2+18a

2a^4-18a^2

Write this square as a trinomial:

(6y + 7x)^2

2007-01-09 02:21:35 · 6 answers · asked by Anonymous in Science & Mathematics Mathematics

6 answers

15a^3 - 6a^2 + 18a
= 3a(5a^2 - 2a + 6)
note: as b^2 < 4ac this cannot be factored any further into real roots

2a^4 - 18a^2
= 2a^2(a^2 - 9)
= 2a^2(a + 3)(a - 3)

(6y + 7x)^2
= (6y + 7x)(6y + 7x)
= 36y^2 + 84xy + 49x^2

2007-01-09 02:33:40 · answer #1 · answered by Tom :: Athier than Thou 6 · 1 0

1) 3a(5a^2 - 2a +6)
2)2a^2(a-3)(a+3)
3) 36y^2 + 49x^2 + 84xy

it is 84xy because it is 7 times 6 (42) twice (so 84)

2007-01-09 02:33:54 · answer #2 · answered by Yoni 2 · 0 0

3a(5a^2-2a+6)


2a^2 (a^2-9)
=2a^2 (a-3)(a+3)


(6y + 7x)^2=36y^2+49x^2+84xy

2007-01-09 02:32:21 · answer #3 · answered by iyiogrenci 6 · 0 0

15a³ - 6a² + 18a

3a(5a² - 2a + 6)

- - - - - - - - - - - -

2a⁴- 18a²

2a² (a² - 9)

2a²(a + 3)(a - 3)

- - - - - - - - - - -

(6y + 7x)² = 36y+ 42xy + 42xy + 49x² = 36y² + 84xy + 49x²

The answer is 36y² + 84xy + 49x²

- - - - - - -s-

2007-01-09 03:25:48 · answer #4 · answered by SAMUEL D 7 · 0 0

3a(5a^2-a2+6) then factor

2a^2(a^2-9) then factor

36y^2 + 84xy + 49x^2

2007-01-09 02:28:00 · answer #5 · answered by jimvalentinojr 6 · 1 0

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2016-12-15 19:30:39 · answer #6 · answered by ? 4 · 0 0

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