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A toilet flush is operated by the compression of air. The air inside the flush has a pressure of 1.0 x 10^5 Pa and a volume of 150 cm^3. When the flush is operated the volume is reduced to 50 cm^3. The temperature of the air remains constant during this process. Calculate the new pressure of the air inside the flush.

2007-01-09 02:21:26 · 2 answers · asked by ♥♥♥shico♥♥♥ 2 in Science & Mathematics Physics

2 answers

This problem can be solved using the formula P1V1/T1 = P2V2/T2. Both T1 and T2 are the same, so they factor out. So....

P1V1=P2V2

P2 = P1V1/V2

P2 = (10^5)(150)/(50)

P2 = 3*10^5 Pa or, aprox. 3 Atm.

2007-01-09 04:08:18 · answer #1 · answered by Roger N 2 · 0 0

yes-sorry could not calculate.

2007-01-09 10:44:56 · answer #2 · answered by AVANISH JI 5 · 0 0

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