Measurements are a field of four different lengths.
51x25x34x36 all in metres
Please also let me know how to calculate.
Thanks In Advance
2007-01-09 02:20:44 · 13 answers · asked by Lochan 1 in Science & Mathematics ➔ Mathematics
I'm a bit confused. Are you saying this field is a quadrilateral with sides of the given lengths? You don't have enough information to find the area, because there are infinitely many different configurations of these sides. Suppose you were told all four sides were 10 m. It could be a square with area 100 m^2, or it could be a parallelogram with angles of 30 degrees and 150 degrees, giving it half the height of the square and an area of 50 m^2. Similarly, without knowing at least one angle in this quadrilateral, it could have any area between a maximum and a minimum, that could theoretically be calculated, but is probably not what the problem intends. Is there a graphic that accompanies this problem and gives extra information?
If you mean that there are four different fields with the given lengths, you would need to know the width of the field, and then the area of the field is just area = width x length.
2007-01-09 02:24:08 · answer #1 · answered by DavidK93 7 · 0⤊ 0⤋
I guess that you are trying to work out the area of the field which is an irregular shape, just draw it out roughly to scale write the dimensions along the sides, then divide it up into squares, rectangles, i guess there might even be a triangle in there if the boundry cuts a corner in which case treat it as a rectangle and divide it by 2, then add up all the areas, easy!!
2007-01-09 03:07:12 · answer #2 · answered by Anonymous · 0⤊ 0⤋
I'm just going to throw this out:
Set up a random quadrilateral with the of given lengths. Draw a diagonal across the quadrilateral and apply Heron's Formula A=√s(s-a)(s-b)(s-c) on each of the two traingles and you get something like:
A1 = √[½(36+34+a) [½(36+34+a) - 36] [½(36+34+a)-34] [½(36+34+a) - a]]
And something similar for A2.
Based on that, I'm going with the somewhat random quess that your answer is:
1/4 a b c d
where a,b,c and d are your four sides. I'm sure there has to be a formula out there, but I don't know it and can't find it easily. Sorry.
2007-01-09 02:39:25 · answer #3 · answered by bequalming 5 · 0⤊ 1⤋
you need to draw it out and split it into a rectangle and a triangle,.
you don't actually need to draw it of course but the pictorial aid will help.
find the area of the rectangle and then of the triangle.
I got 937.5 using you figures.
Length is 51 and height 25
with one length being 34 I made a recatangle 34X25 which has an area of 850
This leaves a triangle of 7 (that's 51-34) m in lkength and 25 m in height. I made this a rectangle and got 175, i then halfed this as it is the triangles area so that's 87.5
87.5 + 850 is 937.5
2007-01-09 02:31:08 · answer #4 · answered by Anonymous · 1⤊ 0⤋
sq. metres extremely is a unit in arithmetic. From wikipedia: The sq. metre (additionally spelled meter, see spelling changes) is the SI derived unit of section, with image m². that is defined because of the fact the element of a sq. whose aspects degree precisely one metre. The sq. metre is derived from the SI base unit of the metre, which in turn is defined because of the fact the size of the path travelled by technique of easy in absolute vacuum throughout a time era of a million?299,792,458 of a 2d. for various shapes, there are diverse strategies of calculating the element of a definite floor. for occasion, for a 4 sided place you could calculate by technique of multiplying the width with the size. The question now could be what do you prefer to calculate? sq. metres is barely a unit.
2016-12-15 19:30:36 · answer #5 · answered by ? 4 · 0⤊ 0⤋
In order to calculate an irregular area, you will need to divide the area into a number of squares or rectangles. These are easily worked out. Then add the total of all sections together.
2007-01-09 02:28:00 · answer #6 · answered by Davy Crockett 3 · 1⤊ 0⤋
measure the length in metres and the width in metres, then simply multiply the length by the width. eg if length is 20 metres and width is 6 metres then area is 20 multiplied by 6 which equals 120 sq metres
2007-01-09 02:30:33 · answer #7 · answered by Radio Detection And Ranging 1 · 0⤊ 2⤋
Just multiply the length by the width. Pretty simple, but as the first answerer says, you need the width.
2007-01-09 02:26:26 · answer #8 · answered by spikypig 1 · 0⤊ 0⤋
What shape is the field?
Difficult to answer a question like this without a diagram.
2007-01-09 02:42:07 · answer #9 · answered by Como 7 · 0⤊ 0⤋
all you do is times length by width. if the field is an odd shape then just break it into sections.
hope that helps.
2007-01-09 02:26:33 · answer #10 · answered by wang eyed lil 3 · 0⤊ 0⤋