Ok i posted before and I did all the sheet of my 30 questions on it and these two have me stumped any help would be great.
1. 20abc²/25bcd
2. x²-y²/6x+6y
Thank you for any help
2007-01-09 02:15:16 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
1)4ac/5d
2)x-y/6
2007-01-09 02:21:03 · answer #1 · answered by Dr Dave P 7 · 0⤊ 0⤋
1. 4ac/5d
2. (x²-y²) = (x+y)(x-y), so it simplfiies to (x-y)/6 (but x cannot equal -y as this would result in division by zero in the original problem)
2007-01-09 10:20:42 · answer #2 · answered by bequalming 5 · 0⤊ 0⤋
[(20/25)*(abc*c/bcd)}
=(4/5)*(ac/d)
=4ac/5d
x^2-y^2=(x+y)(x-y)
now (x^2-y^2) /6(x+y) = (x-y)/6
2007-01-09 10:55:00 · answer #3 · answered by hardik joshi 1 · 0⤊ 0⤋
20sbc² /25bcd = 4ac/5d
- - - - - -
x² - y² / 6x + 6y =
(x - y)(x + y) / 6(x + y) =
x - y / 6
- - - - - -s-
2007-01-09 11:36:33 · answer #4 · answered by SAMUEL D 7 · 0⤊ 0⤋