simpify this (32x5y5)3/5?

Answer 1

I think you meant this - otherwise the question makes no sense:

(32x^5y^5)^(3/5) = (2^5.x^5.y^5)^(3/5)

= (2.x.y)^3

= 8x³y³

IF YOU MEANT THIS:

(32x5y5)3/5? = 32x5y(5/5)3 = 32x5y3 = 32.5.3xy = 480xy

AND IF THIS:

(32x5y5)^(3/5) - that is (32x5y5) to the power of 3/5

If so:

(32x5y5)^(3/5) = ((32x5y5)³)^(1/5)

= ((2.2.2.2.2.5.5.x.y)³)^(1/5)

= ((2^5).(5²).(x.y))³)^(1/5)

= ((2^5.2^5.2^5).(5².5².5²).(x³.y³))^(1/5)

= ((2^5.2^5.2^5).(5.5.5.5.5).5.(x³.y³))^(1/5)

= ((2^5.2^5.2^5).(5^5).5.(x³.y³))^(1/5)

= (2.2.2).5.5^(1/5).x^(3/5).y^(3/5)

= 2³.5.5^(1/5).x^(3/5).y^(3/5)

Answer 2

It seems to me what you are trying to do is raise the expression (32x5y5) to a power, 3/5, because constants usually come before terms containing variables. If that is the case, just evaluate each constant and variable element individually, then multiply them together.

32 = 2^5,

So (32)^3/5 = (2^5)^3/5 = 2^[(5 x 3)/5] = 2^(15/5) = 2^3 = 8.

Similarly, (x^5)^3/5 = x^3 and (y^5)^3/5 = y^3.

Multiplying these three results together, we get:

8(x^3)(y^3).

Answer 3

If there are exponents, then the answer is totally different.

(32x^5y^5) ^(3/5) that would be the fifth root of [(32x^5y^5)^3]
which should be:

2^3x^3y^3 = 8x^3y^3

Answer 4

=(32*25)3/5
=800*3/5
=160*3
=480

Answer 5

Ray Connie R has the right answer.

Answer 6

Do you mean (35x^5y^5)^3/5 or (35x * 5y^5)^3/5

Answer 7

Are these exponents?

If so...32x^3y^3