quadratic equations?

0 ⤊

quadratic equations?

question1 2p^+p-1=0 question2 3x^-10x+3=0

2007-01-09 00:01:23 · 3 answers · asked by STUART A 1 in Science & Mathematics ➔ Mathematics

3 answers

(2p - 1)(p + 1) = 0
p = 1/2
p = -1

(3x - 1)(x - 3) = 0
x = 1/3
x = 3

2007-01-09 00:15:10 · answer #1 · answered by ? 6 · 0⤊ 0⤋

2pÂ² + p - 1 = 0
(2p - 1)(p + 1) = 0
p = -1 or Â½

3xÂ² - 10x + 3 = 0
(3x - 1)(x - 3) = 0
x = 3 or â

2007-01-09 08:19:27 · answer #2 · answered by Tom :: Athier than Thou 6 · 0⤊ 0⤋

1. 2p^2+p-1=0
=>2p^2+2p-p-1=0
=>2p(p+1)-1(p+1)
=>(p+1)(2p-1)=0
Therfore either p+1=0 or 2p-1=0
Or, p=-1 or 1/2
2.3x^2-10x+3=0
=>3x*2-9x-x+3=0
=>3x(x-3)-1(x-3)=0
=>(x-3)(3x-1)=0
therefore x=3 or 1/3

2007-01-09 09:49:05 · answer #3 · answered by alpha 7 · 0⤊ 0⤋