if a=12, b=13, and c=5, find tan C?

Question

need some help....

the casings are right....so what is the answer

Answer 1

you can see c is perpendicular to a
by checking a^2+c^2=b^2.

12*12+5*5=13*13
144+25=169
169=169 so a and c are perpendiculart to each other.
The hypotenus is b
tanC=c/a
tanC=5/12

Answer 2

Here c^2=a^2 + b^2
therefore angel B= 90 degrees
angel C is facing c=5
so we can write tan C = 5/12

Answer 3

Since 5^2 + 12^2 = 13^2 you know that your triangle is right-angled (Pythagoras), with side b being the hypotenuse and so the right angle is at angle B.
Now draw yourself a picture of the triangle (make sure you label angles A B and C the right way round) and you will see that tanC= opposite/adjacent = 5/12

Always draw a picture to help you with trig questions!

Good luck

Answer 4

Clearly.....12^2+5^2=13^2.......so angle B=90 deg....
Now, tan C=c/a=5/12....... simple.....

Answer 5

cosC = (a^2 + b^2 - c^2) / 2ab = (12^2 + 13^2 - 5^2) /(2*12*13) = 12/13
=> sin^2 C = 1 - (12/13)^2 = 25/169
=> sinC = 5/13 (0<=C <= 180 => sinC >= 0)
tanC = sinC/cosC = 5/12

Answer 6

a=12, b=13, c=5
So, B = 90 Degrees.
So, tan C = c/a = 5/12
= 0.41666..

Answer 7

Tan C = opp side/adj side
= 5/12

Answer 8

tan C = c/a (C is angle opp side c )
= 5/12

Answer 9

You get two different answers so you are going to have to do it yourself. My guess is 5/12.

Answer 10

if a is perpendicular than Tan C = 12/5
if c is perpendicular than Tan C = 5/12
b is hypotenuse.