in meiosis 1 out of 4 daughter cells only one is remained active why ?

Answer 1

Meiosis in male germ cells(primary spermatocytes) leads ultimately to four equal speramtids which undergo spermiogenesis to produce four equal sized spermatozoa.

But in the female germ cells(primary oocytes), meiosis I leads to the production of first polar body and secondary oocyte. The first polar body is considerably smaller and hence dies. The remainig secondary oocyte divides equationally by meiosis II to produce ootid and a second polar body. The latter being much smaller dies, leaving only one ootid which subsequently becomes the ovum.The unequal cytokinesis during meiosis serves to put 90% of the cyoplasm to the ootid.
Now back to your specific query I must say that nearly all the cytoplasm containing all the organelles, yolk, including mitochondria are finally contained in the ovum so that the ovum remains viable and can provide the seat for further embryonic development at least up to gastrulation.

Answer 2

This is true for ovum- because the ovum needs to contain sufficient cytoplasm and organelles to support the embryo, during each mitiotic division only one viable cell forms. The others in humans are know as polar bodies and atrophy.

On the other hand spermatozoa are much smaller and have need of only specialised organelles so 4 forms from each germ cell.

Answer 3

because the other three were inactive...as simple as that..