Can some one plz help me figure out this question, I really dont understand how to do it.
A particle moves along the x-axis so that its velocity at any time 't' greater than or equal to zero is given by..... v(t)=3t^2-2t-1.
The position x(t) is 5 for t=2
Find the total distance traveled by the particle from time t=0 until time t=3.
Thank you very much for your help, I really appreciate it!
2007-01-08 17:00:13 · 3 answers · asked by Sir Excalibur 2 in Education & Reference ➔ Homework Help
solve 3t^2-2t-1 for t
(3t+1)(t-1)
t=1, t=-1/3
take the anti derivative of v(t), this will give you the equation of x(t), and of course, C.
plug in 2 for t and 5 for x(t) and solve for C. now you have the position function
Set up 2 different equations:
Plug in 3 for t and 1 for t. Subtract.
Plug in 1 for t and 0 for t. Subtract.
Take the absolute values of each and add them together. That is the total distance traveled.
If you need more explanation just let me know.
2007-01-08 17:26:23 · answer #1 · answered by duhbomb234 2 · 0⤊ 0⤋
you have to use integration
integral of the velocity would be y=x^3-x^2-x+c and by plugging in the intial condition (2,5) shows you that c=3, making the equation y=x^3-x^2-x+3 then you evaluate that with x = 3 and x=0 and subtract them
2007-01-08 17:30:36 · answer #2 · answered by zzzfan14 3 · 1⤊ 0⤋
Is v(t) correct? v(0) = -1.
2007-01-08 17:33:00 · answer #3 · answered by S. B. 6 · 0⤊ 0⤋