This is concerning or involving radicals?

Question

Could I have someone perform the check portion of this problem. The problem: √{3(x+4)}=1+√{2x+7)}
Answer: x=2 or -2

I have tried and tried to perform the check portion, but to no matter how I go about it I can't seem to obtain a true equation. I know I am missing some very basic step, but I can't figure out what it is. (Note the answer is correct I just need the step by step check portion.)

Thanks to all, I really appreciate it.

Sorry everyone, the correct answer is 2√3 or -2√3

If anyone could do the check portion, that would be great. Original problem:
√{3(x+4)}=1+√{2x+7)}

Thanks

Answer 1

The correct answer is x = 2 times the squareroot of 3 or -2 times the squareroot of 3.

Answer 2

Solve for x

√{3(x+4)} = 1 + √{2x+7)}

I notice that you have one stray ")" in the right hand term.
I tried fixing it by removing it and √{2x+7)} became √{2x+7}.
With this change I came up with the solution:
x = ±2√3

Answer 3

Answer is wrong

x = 2
3 sqrt(2) = 1 + sqrt(11) which is not true

x = - 2
sqrt(6) = 1 + sqrt(3) which is not true

Answer 4

It doesn't work, x=4 fits in there though. Try squaring everything to get rid of the root signs maybe, it's been ages since I did maths.

Answer 5

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Answer 6

Yeah, the answer is not correct. What makes you think it is?

Answer 7

Yes I'm glad you asked. No it's wrong

Answer 8

are you sure that the question?