Math Genuises pls help me!! & thank you for those who answered to my previous math questions!i learned a lot!!

Question

thelma's average driving speed is 4 miles per hour faster than richard's. in the same length of time it takes Thelma to drive 364 miles, richard only drives 336 miles. what is thelma's average driving speed?

pls explain step by step. thanks!

Answer 1

This problem utilizes the formula:

time = distance / rate

θ = Thelma's speed
r = Richard's speed
t = time

We have

θ = r + 4
r = θ - 4

t = 364/θ = 336/r
364/θ = 336/(θ - 4)
364(θ - 4) = 336θ
28θ = 4*364 = 1456
θ = 1456/28 = 52 mph

Answer 2

Let T be Thelma's average driving speed. Then Richard's average driving speed is T - 4.

time = distance / rate

Thelma's distance / Thelma's rate =
Richard's distance / Richard's rate

364 / T = 336 / (T - 4)
364T - 364 * 4 = 336T
28T = 1456
T = 52

which is what was asked for.

Answer 3

the answer is simple.

thelma is driving 53 MPH

if you take the difference between the distances of thelma and richard and divide by the speed differential of hte 2 you find that the trip took exactly 7 hours. then divide richards distance of 336 Miles by 7 hours to find that richard is averageing 48 MPH. thus thelma is traveling at an average speed of 52 MPH.

granted that is going to make for an interesting formula but since I figure these things out in my head I can't be much more help here.

Answer 4

i know that the answer is richard drives 48mph and thelma's speed is 52mph. after 7 hours of driving, they travel 336 and 364 miles respectively.

unfortunately i dont have a formula. just did basic arithmetic.

Answer 5

rate*time = distance. Since the times are the same, if you solve this for time (time = distance/rate) then you can set the two equal to eachother.

Thelmas rate (T) = Richard's rate (R) + 4 so

364/R+4 = 336/R

cross multiply

364R = 336R + 1344
28R = 1344
R = 48

But that's Richard's speed. Thelma is R + 4, so her speed is 52 mph. (don't forget to include units in your answer :)

Answer 6

Let r = Thelma's driving speed. Then,
364/r = 336/(r - 4)
364r - 1,456 = 336r
28r = 1,456
r = 52mph

Answer 7

t + 4 = r
t/r = 364/336
solve this and voila the answers

( 2nd formula is derived from ( time is unknown )
time*t = 364
time*r = 336
)

Answer 8

If prepare A is going 30 miles/hour, then the quantity of distance it could bypass in a undeniable time (call it t) is: 30 miles/hour * t hours = 30t miles the 2d prepare starts out 2 hours later, so for it the time this is traveling is t-2. meaning that prepare B (going 40 miles in keeping with hour) can bypass this distance in t-2 hours: 40 miles/hour * (t-2) hours = 40(t-2) miles The question says that prepare B catches up with prepare A (meaning that they bypass the comparable distance), so as meaning: 30t = 40(t-2) remedy for t to discover the form of hours the trains have been traveling.