If i'm understanding correctly, you're asking us to evaluate 4*(x^5), with x being 2.
If that is right, then 4x^5 = 4(2^5) = 4(32) = 128
P.S.: The caret symbol (^) can be used to denote exponents
2007-01-08 14:51:47
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answer #1
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answered by Anonymous
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What is 4x5 but five is an exponet, when x = 2?
4x^5 = 4(2)^5 = 4 *32 = 128
2007-01-08 22:52:59
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answer #2
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answered by ironduke8159 7
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That's easy
You plug in 2 for x so the equation is 4 x 2^5
Then you do 2^5 which is 32 then multiply by 4 which is 128
2007-01-08 22:56:16
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answer #3
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answered by Anonymous
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Remember PEMDAS (parethesis, exponents, multiply, divide, add, subtract) in that order.
Exponent first: x^5 where x=2 is 2^5 is 32
Multiply second: 4 x 32 = 128
2007-01-08 22:53:58
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answer #4
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answered by radon360 4
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4(2)^5 = 128
2007-01-08 22:51:06
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answer #5
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answered by Anonymous
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4x^5 when x=2
4(2^5)=4*32=128
2007-01-08 22:52:48
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answer #6
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answered by Professor Maddie 4
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4.2.5 = 40 4x2=8 8x5=40 simple algebra
2007-01-08 22:51:48
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answer #7
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answered by Anonymous
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