The electron pair in a C-F bond could be considered?

Question

[A] closer to C because carbon has a larger radius and this exerts greater control over the shared electron pair.
[B] closer to F because flourine has a higher electronegativity than carbon.
[C] closer to C because carbon has a lower electronegativity than flourine.
[D] an inadequate model since the bond is ionic
[E] centrally located directly between the C and F.

Answer 1

Letter B is the correct answer. Fluorine has the highest electronegativity value of all the elements. That means it exerts a larger attraction for the shared electrons in the C-F bond. The larger attraction will hold the electrons closer to the F than the C.

Answer 2

B. Fluorine is the most electronegative element in the periodic table, therefore the electrons will be closer to F

Answer 3

[B]