exponent....?

Question

(x^5 + x^ -2) / x^3

In words:

x to the 5 power plus x to the -2 power over (divided by) x to the 3 power.

Answer 1

(x^5 + x^(-2)) / x^3

It is proper math etiquette to have all exponents positive, so that's what we have to do; get rid of x^(-2). First, let's make it a fraction; note that any negative exponents can be made positive by putting 1 over the positive power.

(x^5 + 1/x^2) / x^3

It is also proper math etiquette to not have complex fractions (fractions within fractions). We get rid of the complex fraction by multiplying numerator and denominator by x^2.

x^2(x^5 + 1/x^2) / (x^3 * x^2)

Distribute the x^2 on the top.

(x^7 + 1) / (x^5)

That's it!

Answer 2

(x>5 + x>-2)/x>3

Answer 3

x^2 + x^-5

Answer 4

You can't simplify this by adding the exponents, this only works for multiplication. I would simplify this into 2 fractions:

(x^5 / x^3) + (x^-2 / x^3)
x^2 + (1 / x^5)
-OR-
x^2 + x^-5

Answer 5

First I would break this up into 2 fractions:

(x^5+x^-2)/(x^3)
(x^5/x^3) + (x^-2)/(x^3)

Now simplify as much as possible
x^2 + (x^3)(x^2)
x^2 + x^5

You can't add these since they have different exponents.

Answer 6

yea we learned that n class but didnt really get it?