.hi..........................i need urgent help in maths?

Question

Four sister met for a birthday dinner.The sum of their ages was 100.April was the oldest and Tiffany the youngest.Cassandra is 10 years older then Winona.What is the age of Tiffany could be.

Answer 1

C = W+10
A>C -> C>W+10
C+A+W+T = 100
T
The smallest C could be is W+11, so T + W + W+10 + W+11 = 100
T+3W=89 and T
1<= T <= 20

Answer 2

Tiffany could be 1 or even 0 trivially and any number higher up to 19, assuming they are all of different ages. If Tiffany is 19, Winona is 20, Cassandra is 30 and April is 31 = 100

If Tiffany were 20, Winona would be at least 21, Cassandra would be at least 31, and April would be at least 32 which totals to at least 104.

So tiffany's age could be anywhere from 0 through 19.

Answer 3

For any algebraic word problem, what you want to do is assign the variable to the person who is being compared to the most. It says April is the oldest, tiffany is the youngest, and then we see someone being compared to Winona.

Let w = Winona's age. Then,
w + 10 = Cassandra's age.
Let a = April's age
t = Tiffany's age.

Therefore,

w + (w + 10) + a + t = 100
2w + 10 + a + t = 100
2w + a + t = 90

There's not enough information to obtain Tiffany's age, but it could be just me; I'll observe the other solutions and possibly learn from them.

Answer 4

Let age of April = x
age of Winona=y and
age of Tiffany=z
age of Cassandra= y+10 (Since Cassandra 10 yrs older than Winona)
therefore x+y+z+(y+10)=100
z=90-x-2y

Answer 5

A>C=10+W>W>T

A+C+W+T = 100

or

A+2W+10+T = 100

Solve for T,
T = 90-(A+2W)

Pick W closest to T to have maximum T,
W = T+1
Pick A closest to T to have maximum T,
A = 11+W = T+12

T = 90-(T+12+2T+2)
4T = 76
T = 19

Therefore, T is less than or equal to 19.

Check:
T=19
W=20
C=30
A=31

T=20
W=21
C=31
A=28 to match to total 100. But A