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Problem: 6 different numbers are chosen from the set {1, 2, 3, ..., 44}. The winning numbers are drawn from this set. To win, all 6 numbers must be matched in any order.

Question: What is the probability of winning, P(winning)?

Note: You may use nCr and/or nPr in your answer. Please explain thoroughly.

I genuinely appreciate all and any effort.

2007-01-08 11:35:38 · 2 answers · asked by Esse Est Percipi 4 in Science & Mathematics Mathematics

2 answers

1/44C6, right?

There's only one "group" that wins...and there are 44C6 ways to choose a group of 6.

2007-01-08 11:39:23 · answer #1 · answered by Jim Burnell 6 · 1 0

Since order does not matter, there are 44C6 possible winning combinations. The probability of winning therefore is 1/ that number.

2007-01-08 19:39:35 · answer #2 · answered by hayharbr 7 · 1 0

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