Overseas adoptions have increased by more than 200% fromn 1992 to 2002. In 1992, 6332 visas were issued to orphans from other countries. In 2002, 20,084 visas were issued. Find the average rate of change in the number of oversea adoptions over the 10 year period.
2007-01-08 11:14:37 · 6 answers · asked by ♥Princess♥ 4 in Education & Reference ➔ Homework Help
1902 to 2002 is a 10 year period and, so, if the growth had been linear, the annual growth would have been 200/10 = 20% per year .
You could say increase was 20,084 - 6332 ie 13,752
this represents 13,753/10 per year ie 1375 per year.
1375/6332 x 100 gives the percenatag per year.
ie approx 21.7%
However this is an average. The growth has probably not been linear. There would have peeks and troughs. Things like famine, disasters etc cause peaks.No notable news can cause troughs.
2007-01-08 11:24:38 · answer #1 · answered by jemhasb 7 · 0⤊ 0⤋
you should do your own homework. I will help you though, but I wont give you the answer. First, you have to find how much change has occured. So by how much has the # of adoptions increased- that is, what is the difference of the 2002 measurement from the 1992? Now you divide this number by the time period.
If you need to know the change in percent, just divide the 2002 measurement by 1992, giving you the change over a 10 year period. Now that you have it for the 10 year period, what amount of change would you have per year? Just divide the percent by 10.
2007-01-08 11:26:39 · answer #2 · answered by Anonymous · 0⤊ 0⤋
speed is a ratio, distance divided by potential of time, d/t = r a proportion is an equation that proclaims 2 ratios are equivalent subsequently meaning the fee is persevering with. the question, "how some distance might it holiday" implies no exchange in speed. so 1234 m / 30 min = x m / seventy 5 min, or merely, 1234/30 = x/seventy 5 to clean up a proportion, go multiply, then divide. 30x = 1234 • seventy 5 x = 1234 • seventy 5 / 30 x = 3085 m
2016-11-27 21:00:38 · answer #3 · answered by comella 4 · 0⤊ 0⤋
Can you provide the formula?
I think this is it
'rate of change = 20,084 - 6332/10
2007-01-08 11:22:51 · answer #4 · answered by piglet564 3 · 0⤊ 0⤋
It's been a while since I've taken a math class, but here's my guess. 1375.2 adoptions per year. Rounded down that would be 1375 per year.
You're not going to have fun in calculus.
2007-01-08 11:25:15 · answer #5 · answered by captainjackson2004 2 · 0⤊ 0⤋
HUH?????
2007-01-08 11:20:14 · answer #6 · answered by kendallyn collins 1 · 0⤊ 0⤋