7th grade Math Help?

Question

This problem says find the distance between A(3,8) and B(-5,2). Then find the coordinates of the midpoint of AB.

Answers plz!!!

FYI not stupid just lazy

Answer 1

Distance = 10
Midpoint = (-1,5)

The distance is from the Pythagorean Theorem: (x1 - x2)^2 + (y1 - y2)^2 = distance^2 = (3 - (-5))^2 + (8 - 2)^2 = 8^2 + 6^2 = 64 + 36 = 100 = distance squared, so the distance equals the square root of 100 which is 10.

The midpoint is done by adding each coordinate, x1 + x2 and dividing by 2, then y1 + y2 and dividing by 2: (3 + -5)/2 and (8 + 2)/2 and so: -1 and 5 or: (-1,5).

Answer 2

set up a right triangle on the graph. that way you can use pythagorean theory. a^2 + b^2 = c^2

set the corner with aright angle at (3,2). thats where a straight vertical line down from point A meets a horizontal line from point B. call this point C

you must now find the distance from point A-C and Point B-C. this will make up the a and b of the equation. C is the distance.

with simple subtraction you can get A-C to be 6 and B-C to be 8

6^2 + 8^2 = C^2 >>>> 36+64 = square root of 100 = 10 that means the distance is 10! and thats your answer

Answer 3

the other two ppl r wrong listen to me i know this

ok so the x coordinate of A is 3 and the x coordinate of B is -5 so the distance between them is 8 right (thats basicly that boxes)

ok so the y coordinate of A is 8 and the y coordinate of B is 2 so the distance between those two are..... 6 right

so then u have a x coordinate that is 8 right (the first explination)

and then u have a y coordinate that is 6 right (the second expliation)

so then your midway point is (6,8) hope that didnt confuse you to much stick with it bc if u dont get this u r going to die in the 8th grade bc that is pre alebra right ...alegabre is like wow

Answer 4

Plot the points, draw the line, use a ruler, find the length, find the midpoint, write down the coordinates of the midpoint. Done.

Answer 5

distance = squareroot((8-2)squared)+(3-(-5))squared)
= squareroot(6squared + 8squared)
= squareroot(36 + 64)
= squareroot(100)
= 100

midpoint(x,y) = ((3+(-5))/2 , (8+2)/2) = (-1,5)

Answer 6

A = (x1, y1)
B = (x2, y2)
Midpoint M = (x, y)

Distance formula
D = sqrt((x1-x1)^2 + (y1-y2)^2)

Midpoint
(x, y) = ((x1+x2)/2, (y1+y2)/2)

sqrt means the square root. ex. sqrt(4) = 2
^2 means raised to the power of 2. ex. 2^2 = 4

I think you can do it from here?

Answer 7

Lanatullahi alaik.

Answer 8

this is exactly the homework i had tonight except for the fact that im in 8th grade and im in the advanced algebra class. what class are you in??

Answer 9

http://regentsprep.org/Regents/math/midpoint/Lmidpoint.htm

i know by the time i put this up someone wil have answered it but i hope this helps

Answer 10

you should go to aaamath.com there they help you with EVERY THING IN MATH all the way up to 9th graders try it!hope you get the help you need