2007-01-08 10:03:56 · 7 answers · asked by girlsrule688 1 in Science & Mathematics ➔ Mathematics
x + (x+1) = 21
2x + 1 = 21
x = 10
i.e. 10 & 11 are the 2 numbers
2007-01-08 10:05:49 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Are the consecutive integers even or, odd? If its neither, here the equation. 1st number = x + 1 and 2nd number = x + 2
*Combine the equations and set them to equal 21 >
x + 1 + x + 2 = 21
First: combine "like" terms >
2x + 3 = 21
Sec: subtract 3 from bohth sides (opposite sides means opposite sign) >
2x + 3 - 3 = 21 - 3
2x = 18
Third: solve for "x" by isolating it on one side > divide both sides by 2 >
2x/2 = 18/2
x = 9
*Last step - replace both "x" variables with 9 in both equations >
x + 1
9 + 1
10
x + 2
9 + 2
11
The numbers are 10 and 11
2007-01-08 10:11:06 · answer #2 · answered by ♪♥Annie♥♪ 6 · 0⤊ 0⤋
x + (x+1) = 21
2007-01-08 10:06:05 · answer #3 · answered by Uncle Remus 4 · 0⤊ 1⤋
X + (X+1)=21 // 2x+1=21
2X+1=21
-1 -1
________
20
----- = 10 (X=10)
2
One # is 10 and add 1 to X which will equal 11
So the #'s are 10,11
2007-01-08 10:06:13 · answer #4 · answered by Dr. Nick 6 · 1⤊ 0⤋
X + (X + 1 ) = 21
Solve for X and X + 1
2007-01-08 10:05:53 · answer #5 · answered by Qwyrx 6 · 2⤊ 0⤋
x + (x + 1) = 21
The numbers are 10 and 11
2007-01-08 10:06:08 · answer #6 · answered by Master of All He Surveys 2 · 0⤊ 1⤋
N + (N+1) = 21
2N + 1 = 21
2N = 20
N = 10
Answer: 10,11
2007-01-08 10:06:47 · answer #7 · answered by vejjev 2 · 1⤊ 0⤋