A metal sphere has a charge of +7.0 µC. What is the net charge after 8.00 1013 electrons have been placed on it.
2007-01-08 09:41:45 · 3 answers · asked by larkinfan11 3 in Science & Mathematics ➔ Physics
First, I am assuming the number of electrons is 8.00 x 10^(13).
Each electron carries a charge of -1.602 x 10^(-19) coulombs. The product of these two numbers is -12.816 x 10(-6) coulombs or -12.816 microcoulombs. Adding this to the original charge of 7.0 microcoulombs yields a net charge of -5.816 microcoulombs, or -5.8 μC after rounding to two significant figures.
2007-01-08 10:06:49 · answer #1 · answered by hevans1944 5 · 0⤊ 0⤋
charge of electron=1.6*10^(-19)c
charge of electrons=1.6*10^(-19)*8.00 1013 c
net charge=7+1.6*10^(-19)*8.00 1013 c
2007-01-08 17:46:34 · answer #2 · answered by a 3 · 0⤊ 0⤋
I believe: 7x10^-6-(8001013(1.63x10^-23)) C
2007-01-08 17:45:14 · answer #3 · answered by Robert B 1 · 0⤊ 0⤋