A) 92U235
B) 92U239
C) 93Np239
D) 94Pu239
2007-01-08 07:50:26 · 5 answers · asked by frickenawesomekoreanandyouknowit 2 in Science & Mathematics ➔ Chemistry
92U235 has 235-92, or 143 Neutrons.
92U239 has 239-92, or 147 Neutrons.
93Np239 has 239-93, or 146 Neutrons.
94Pu239 has 239-94, or 145 Neutrons.
Therefore 92U239 has the largest number of neutrons.
2007-01-08 07:55:35 · answer #1 · answered by Patrick M 2 · 0⤊ 0⤋
it suppose to be 92U239 since the neutrons number is the diffrience between the mass number (239) to the atomic number (92)
so no of neutrons would be 239-92=147 neutron
but what i know that 92U239 isn't a stable isotope and it will decay to form 93NP239 with emitting of a Beta radiation and it will emitt another Beta radiation in order to get 94Pu239
so if you talk about just a structure with mass number and atomic number it would be
B)92U239
but if you talk about a real atom with stability it will be
D)94Pu239
since you can't get 92U239 in nature as it decay as what shown above
.....................
good luck
2007-01-08 07:57:46 · answer #2 · answered by ch_yaso 2 · 0⤊ 0⤋
B. Subtract the atomic number from the mass number to get the number of neutrons.
2007-01-08 07:53:19 · answer #3 · answered by hcbiochem 7 · 0⤊ 0⤋
B) 92U239
It contains four more neutrons than 92U235, and a neutron becomes a proton by beta decay to produce 93Np239 and 94Pu239 successively.
2007-01-08 07:55:53 · answer #4 · answered by novangelis 7 · 0⤊ 0⤋
Calculate to get answer B. But once again, is there in fact such a species of Uranium?
2007-01-08 07:58:24 · answer #5 · answered by Carol L 1 · 0⤊ 0⤋