With a plentiful supply of air, 3.0 parts carbon reacts with 4.0 parts oxygen to produce carbon monoxide. use this mass ratio to calculate how much carbon is required to produce 990g of carbon dioxide. the answer is 270 but how the hell this that happen?
2007-01-08 06:24:49 · 4 answers · asked by maya 4 in Science & Mathematics ➔ Chemistry
If so easy answer it yourself.
2007-01-08 06:32:42 · answer #1 · answered by Lil' Gay Monster 7 · 0⤊ 0⤋
Let pt be any arbitrary weight.
3pt C + 4pt O2 ===> 7pt CO
The 3 and 4 are given; the 7 comes from conservation of matter.
3pt C + 8pt O2 ===> 11pt CO2
The 8 comes from the twice as much oxygen needed to make CO2 from 3pt C; the 11 comes from conservation of matter.
990gCO2 x 3gC/11gCO2 = 270gC
The 990 is the amount CO2 wanted. 3g C per 11g CO2 comes from substituting g for pt. It's the ratio that matters. The gCO2 cancel, leaving gC, which iswhat was wanted.
2007-01-08 14:58:45 · answer #2 · answered by steve_geo1 7 · 0⤊ 0⤋
You end up with 22.5 moles of CO2, right? So you had to start with 22.5 moles of C and 22.5 moles of O2, so 22.5 moles of C = 270 g! FYI - 22.5 moles of O2 = 720g, and 270 +720 = 990; conservation of matter!
2007-01-08 14:41:19 · answer #3 · answered by lynn y 3 · 0⤊ 0⤋
It's GODs will.The devil made me answer this.
2007-01-08 14:37:18 · answer #4 · answered by Anonymous · 0⤊ 0⤋