Step-by step please, just can't solve it
Evaluate if a= 3 and b= -2
1. 4 + ab2 <-the 2 is an exponent
2. (4+ab)2 <-2 is also an exponent
2007-01-08 04:25:46 · 7 answers · asked by James A 1 in Science & Mathematics ➔ Mathematics
1. 4 + ab^2
First: replace 3 with the "a" variable and -2 with the "b" variable >
4 + 3(-2)^2
Sec: solve according to order of operations (PEMDAS) >>>
( ), exponents, multiplication, division, addition & subtraction
4 + 3(4)
4 + 12 = 16
2. Follow the same format as number (1) > replace numbers with the variables.
(4 + ab)^2
(4 + 3(-2))^2
(4 - 6)^2
(-2)^2
= 4
2007-01-08 05:38:13 · answer #1 · answered by ♪♥Annie♥♪ 6 · 0⤊ 0⤋
This is quite simple just substitute in the given variables as follows
1. 4+(3)(-2)(-2) since b is squared
= 4+3(4)
= 4+12
=16 Answer
The brackets take the priority (BODMAS)
I.e B--Brackets, O-Of, D--Division, M--Multiplication, A--Addition,S--Subtraction.
2.(4+ab)(4+ab)
=(4+(3)(-2))(4+3(-2))
=(4-6)(4-6)
=(-2)(-2)
= 4 Answer
2007-01-08 12:43:28 · answer #2 · answered by jodesy 1 · 1⤊ 0⤋
4 + ab^2
= 4 + 3 * (-2)^2
= 4 + 3 * 4
= 16
(4+ab)^2
= (4 + 3 * -2)^2
= (4 - 6)^2
= -2^2
= 4
2007-01-08 12:30:34 · answer #3 · answered by Tom :: Athier than Thou 6 · 1⤊ 0⤋
a=3; b=-2
1. 4 + ab^2
4+3*(-2)^2
4+3*4
4+12
16
2. (4+ab)^2
(4+3*(-2))^2
4-6)^2
(-2)^2
4
2007-01-08 13:23:17 · answer #4 · answered by yupchagee 7 · 1⤊ 0⤋
4+ab^2
4+3 x -2^2
4+3 x -4
-8
(4+ab)^2
(4+-6)^2
(-2)^2
4
2007-01-08 13:31:17 · answer #5 · answered by Saphira 3 · 0⤊ 1⤋
1. 4+3(-2)^2=16
2. (4-6)^2=4
2007-01-08 12:31:17 · answer #6 · answered by Maths Rocks 4 · 0⤊ 0⤋
1) 4+(3)(-2)^2 = 4 + 12=16
2) (4+(3)(-2))^2 = (-2)^2 = 4
2007-01-08 12:28:49 · answer #7 · answered by Patrick M 2 · 1⤊ 0⤋