What is the derivative of cos (x^2-1/ln x)?

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2007-01-08 04:18:56 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

I'm trying to use up my questions so I can stop wasting my time on here. I can't think of anything else to ask.

2007-01-08 04:23:13 · update #1

-sin(x^2-1/lnx)*[2x+1/x(ln x)^2]

2007-01-08 04:20:12 · answer #1 · answered by Anonymous · 0⤊ 0⤋

are you Asian? I mean who think about Math....

2007-01-08 12:20:55 · answer #2 · answered by Anonymous · 0⤊ 0⤋

y=cos[x^2-1/lnx]
y'=-sin[x^2-1/lnx]*[2x-{lnx*0-1*1/x}/lnx^2]
=-[2x+1/x*lnx^2]*sin[x^2-1/lnx]

2007-01-08 12:31:21 · answer #3 · answered by openpsychy 6 · 0⤊ 0⤋

wat canopy said.

2007-01-08 12:25:22 · answer #4 · answered by Maths Rocks 4 · 0⤊ 0⤋