CAN SOMEONE HELP me with MAth!!?

Question

1,Which polynomial is irreducible and prime?
A. 2a^2 - ab-b^2
B.2a^2- 3ab + b^2
C.2a^2- 3ab- b^2
D.2a^2 + ab - b^2

Solve each equation and be sure to note any double roots

1. 3x^2 -2x = 8
a. 3/4, 2
b. -4/3, 2
c. 3/4, -2
d. -4/3, -2

2. x^4 - 5x^2 + 4= 0
a. -2, -1, 1,2
b. -2, -1
c. 0,1,2, 0 is the double root
d. -1,0,2, -1 is a double root

Answer 1

1,Which polynomial is irreducible and prime?
A. 2a^2 - ab-b^2 = (2a+b)(a-b)
B.2a^2- 3ab + b^2 = (2a-b)(a-b)
C.2a^2- 3ab- b^2 <-- this is prime
D.2a^2 + ab - b^2 = ((2a-b)(a+b)

Solve each equation and be sure to note any double roots

1. 3x^2 -2x = 8
x= [2 +/- sqrt(4 -4*3(-8))]/6 =(2 +/- 10)/6 = 2 or -4/3
a. 3/4, 2
b. -4/3, 2
c. 3/4, -2
d. -4/3, -2

2. x^4 - 5x^2 + 4= 0
let y = x^2 --> y^2 -5y +4 = 0 = (y-4)(y-1) so y = 4 or y = 1
x = sqrt(y) = 2, -2. 1, -1 so a. is the answer.
a. -2, -1, 1,2
b. -2, -1
c. 0,1,2, 0 is the double root
d. -1,0,2, -1 is a double root

Answer 2

A. 2a^2 - ab - b^2 = (2a + b)(a - b)
B.2a^2 - 3ab + b^2 = (2a - b)(a - b)
C.2a^2 - 3ab - b^2 = Prime
D.2a^2 + ab - b^2 = (2a - b)(a + b)

1.
3x^2 - 2x = 8
3x^2 - 2x - 8 = 0
(3x + 4)(x - 2) = 0
Roots are -4/3 and 2 (d)

2.
x^4 - 5x^2 + 4 = 0
(x^2 - 4)(x^2 - 1) = 0
(x + 2)(x - 2)(x + 1)(x - 1) = 0
Roots are -2, -1, 1, 2 (a)