Tough math question?

Question

The product (sin a) (cos a) (tan a) (sec a) (cot a) is equivalent to...?

Answer 1

change tan,sec,cot to sin,cos,and tan .
everything cancels out and the result=(sin a)
the above product is not appropriate because we can replace cot with tan where it is not defined and so the others also.
please note it is possible in certain intervals only.
FOR EXAMPLE:::
cot(pie/2) is defined but tan(pie/2) is not pie/2 is out of it's domain.

always see that u replace the functions with their eq. only.

Answer 2

(sec a)(cos a) = 1
(tan a)(cot a) = 1

(sin a)(cos a)(tan a)(sec a)(cot a) = (sin a)

Answer 3

tan a = (sin a) /(cos a)
cot a =(cos a)/ (sin a)
sec a = 1/(cos a)

thus rewriting it and canceling terms you get :
sin *cos * (sin/cos) * (1/cos) * (cos/sin) = sin a

Answer 4

(sin a)(cos a)(tan a)(sec a)(cot a)
=sin a*cos a*sin a/cos a*1/cos a*cos a/sin a
=sin a

Answer 5

SIN A.

tan a = sin a / cos a
sec a = 1 / cos a
cot a = cos a / sin a

(sin) (cos) (sin/cos) (1/cos) (cos/sin)
everything cancels out except sin

equivalent to sin a.
Simple.

Answer 6

Recall that (sin a) = opposite/hypoteneuse.

Plug in the similar definitions for the other functions and simplify.

Answer 7

sin a

(Cot a) and (tan a) get cancelled
(cos a) and (cosec a) get cancelled

Answer 8

It is equal to 1

tan(a)=sin(a)/cos(a)
sec(a)=1/cos(a)
csec(a)=1/sin(a)
ctan(a) =cos(a)/sin(a)

sin(a) cos(a) [sin(a)/cos (a)] 1/cos(a) cos(a)/sin(a)=
=1

BTW MamaMia below has the most elegant grouping.

Answer 9

Numeric