wht should be the output of the following program??

Question

#include
main()
{
int a=5;
a=(--a)-(a--);
printf("%d",a);
}

Answer 1

it should print. I don't know I give up.

Answer 2

well, the a value assignment is easy, --a=4 - a--=4 (it should reassign 3 after the value is read, but since were reassigning to a, it doesn't matter), a=0. now, the printf function should print a signed decimal integer: 0.00

Cheers

Answer 3

Answer is Zero.

Reason:-
--a-> indicates pre-decrement. so it will decrement and also assign. so now value of a=4,
(--a)-(a--)
4-(4--);
a-- => will be decremented only after seeing semi-colon
so at present a=4-4 =0
so again, after semicolon a gets decremented.
So a=-1
When u are printing, you are printing it as integer ie. %d, so answer will be zero. ( i am not sure about the printed answer) but the rest of the steps are correct.

Answer 4

zero