Solve this equation 3x² + 5x + 1 = 0 ?

Question

i have a complete mind blank
its fustrating me

thank you

x

i think it might just need factorising?!

Answer 1

you can use the quadratic formula, wich is:

ax² + bx + c = 0

x= (-b ± √b² - 4ac) / 2a

so it will be:
a=3
b=5
c=1

so

x= (-5 ± √5² - 4*3*1) / 2*3
x=(-5 ± √25 - 12) / 6
x=(-5 ± √13) / 6
x=(-5 ± 3.605551275) / 6

so x1=(-5 - 3.605551275) / 6 = -1.434258546

or x2=(-5 + 3.605551275) / 6 = -0.232408121

we can prove it if we substitute the value in x, for example:
x= -1.434258546

3x² + 5x + 1 = 0
3(-1.434258546)² + 5(-1.434258546) + 1 = 0
6.17129273 + -7.17129273 + 1 = 0

PLEASE let me know if you need any additional explanation

Answer 2

If the made from 2 numbers, right here represented by way of 3x + a million and 5x - 4, is 0 than all of us comprehend that could be real if both one among them were = to 0. So, putting each to 0 and fixing we get right here if 3x+a million=0, then 3x=-a million and for this reason x=-a million/3 if 5x-4=0, then 5x=4, and for this reason x=4/5

Answer 3

*You have to use the Quadratic Equation.
The Quad equation is x = [- b + /- V`(b^2 - 4ac)] / 2a
*Note (V` represents a radical sign/square root)

First: determine the "a", "b", and "c" variables >>>

a = 3, b = 5, and c = 1

Sec: place the coefficients in the quad equation >

x = [- 5 +/- V`(5^2 - 4(3)(1)] / 2(3)
x = [- 5 +/- V`(25 - 12) / 6
x = [- 5 +/- V`13] / 6

Third: you will have two separate equations, one with addition and the other with subtraction.

1. x = [- 5 + V`13] / 6
x = -5/6 + (V`13)/6

2. x = [- 5 + V`13] / 6
x = - 5/6 - (V`13)/6

Answer 4

First try to factor the problem, if it will. If it won't factor, use the quadratic formula to solve the problem.


3x^2 + 5x + 1 = 0

a = 3, b = 5 and c = 1

x = [ - b + or - ( b^2 - 4 ac )^ 1/2 ] / 2a

[-5 + or - (25 -12)^1/2 ] / 6

[-5 + (13)^1/2] /6 or [-5 - (13)^1/2] / 6

Answer 5

3x² + 5x + 1 = 0

a = 3

b = 5

c = 1

- - - - - -

Quadratic Formula

x = -b ± √b² - 4ac / 2a

x = - 5 ± √(5)² - 4(3)(1) / 2(3)

x = - 5 ± √25 - 12 / 6

x = - 5 ± √13 / 6

The answer is x = - 5 ± √13 / 6

- - - - - - - - -s-

Answer 6

X=-b±(b² - 4ac)^1/2/2a
X=(-5±(25-12)^1/2)/6
X= (-5±(13)^1/2)/6
X=(-5±3.61)/6
X=(-1.39)/6 or X=(-8.61)/6
X= -0.232 or X= -1.435

Equation does not factorise.

Answer 7

-5 + or - radical13 on 6

Answer 8

ax² + bx + c = 0
delta=b²-4.a.c
x1=(-b-square root of delta)/(2*a)
x2=(-b+square root of delta)/(2*a)

let us find delta in the equation 3x² + 5x + 1 = 0.
delta=5²-4.3.1=13

x1=(-5-square root of 13)/(2*3)
x2=(-5+square root of 13)/(2*3)

x1=-1,434258546
x2=-0,232408121

Answer 9

this equation is called a quaratic equation in algebra.
there are 4 methods of solving it
1. by completing the square
2. by factorisation
3. by graph or
4. by formula

Answer 10

quadratic equation

y = (-5 +/- sqrt(5^2-4*1))/(2*1) = (-5 +/- sqrt(13))/2