probability numerical. please solve and give exact detailed answer to be given?

Question

1) A bag contains 10 red,5 white and 4 blue balls. if 4 balls are drawn at random, determine the probabilty that (i) all 4 are blue balls and (ii) 1 red and 2 white.
2) In an experiment on pea breeding, Mendel obtained the following frequencies of seeds: 315 round and yellow; 101 wrinkled and green; 32 wrinkled and yellow ; total were 556 seeds.(we will get round and gree by subtracting from total, i think). Theory predicts that the frequencies would be in the proportion 9:3:3:1.Does the experimental results support the theory? please give all details needed. thank so much who solves.

Answer 1

I donno how to type the answer correctly.hope this helps!!

1) (i) 1
________
19!/15!.4!


(ii) 10.10.4
_________
19!/15!.4!

Answer 2

1.i. (4/19)*(3/18)*(2/17)*(1/16) = 2.6^-4
ii. (5/19)*(2/18)*(1/17) =1.7^-3

2. RY=0.566, WG=0.182, WY=0.058
RG=(556-315-101-32)/556=0.192

Multiply each by 1/0.058 to normalize:
RY=9.75, WG=3.14, WY=1, RG=3.3

Pretty close! I'd say the theory is supported!

Answer 3

In ordinary english: chance of having one particular sequence of the three playing cards is a million/(55*fifty 4*fifty 3). when you consider that any sequence is fantastic, multiply that chance through the style of procedures you may draw the three playing cards, that's 3! (3 factorial). So the chance you get all 3 in any order is 3!/(55 * fifty 4 * fifty 3). that's an party of a mixture formulation as different from a Permutation formulation, which may note to at least one particular order and for your party is basically a million/55 * a million/fifty 4 * a million/fifty 3. on your 2d question, chance of not getting any of the playing cards is fifty 2/55 on the first draw, 51/fifty 4 on the 2d, etc as a lot as 30 attracts. when you consider that each and every one of those events ought to happen you multiply the possibilities of each and every, getting fifty 2*51*...*23/(55*fifty 4*...*26). note all the cancellation you may do, which leaves 25*24*23/(55*fifty 4*fifty 3). Do you spot a regular formulation rising right here, with reference to the style of complete gadgets, the style of wanted (or undesired) gadgets, and the style of gadgets you draw? And an same formulation for the first question? in case you google "permutation mixture" you will see that how the formulation are oftentimes written. They use a fragment mutually with countless factorials (and ensuing cancellations) to exhibit the reply.

Answer 4

It looks like you've posted every one of your statistics problems. You really should at least try to solve them yourself.