It has been estimated that about 30% of frozen chicken contain enough salmonella bacteria to cause illness if improperly cooked. A consumer purchases 12 frozen chickens. What is the probability that the consumer will have more than 6 contaminated chickens? solve the question on basis of binomial probabilty distribution or probability.
2007-01-07 19:55:24 · 4 answers · asked by Jagdeep g 1 in Science & Mathematics ➔ Mathematics
Probability is: P(7) + P(8) + P(9) + P(10) + P(11) + P(12)
P(x) = 12Cx * (0.3)^x * (0.7)^(12-x)
where: 12Cx is the number of combinations size x which can be made from a group size 12.
P(7) = 12C7 * (0.3)^7 * (0.7)^5 = 792 * 0.002 * 0.168
= 0.029
Similarly, P(8) = 0.008 P(9) = 0.001 etc.
They add up to give: 0.0386
If you have a copy of MS Excel, you can calculate P(7) with:
= Binomdist(7, 12, 0.3, FALSE)
2007-01-07 20:19:25 · answer #1 · answered by Alan 6 · 3⤊ 0⤋
a million.i. (4/19)*(3/18)*(2/17)*(a million/16) = 2.6^-4 ii. (5/19)*(2/18)*(a million/17) =a million.7^-3 2. RY=0.566, WG=0.182, WY=0.058 RG=(556-315-one hundred and one-32)/556=0.192 Multiply each by 1 million/0.058 to normalize: RY=9.75, WG=3.14, WY=a million, RG=3.3 fairly close! i might want to assert the idea is supported!
2016-12-02 00:02:28 · answer #2 · answered by ? 4 · 0⤊ 0⤋
Nice answer Alan.
2007-01-07 21:31:30 · answer #3 · answered by Northstar 7 · 1⤊ 0⤋
3.86%
try this online calculator,... may be helpful.
2007-01-07 20:11:32 · answer #4 · answered by beanie_boy_007 3 · 0⤊ 0⤋