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A buoyant force is measured at 5 lb ft/sec2. When weighted in open air, the ball weighs 3 lb. What is the density of the ball?

2007-01-07 19:36:34 · 1 answers · asked by captg1526 1 in Science & Mathematics Physics

1 answers

I'm assuming that the ball was completely submerged under the liquid, then

V=(Fb )/p
V= volume of the liquid displaced
Fb buoyant force
W - weight of the ball
p - density of the liquid

The ball's density is
pb=W/V
or
pb=(W p)/(Fb )

pb=3p/(5)=0.6p

I hope that helps

since p for water is 62.4 lb/ft^3
then
pb= .6(62.4 lb/ft3)= 37.44 lb/ft^3

2007-01-07 23:45:57 · answer #1 · answered by Edward 7 · 0 0

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